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495=10t-5t^2
We move all terms to the left:
495-(10t-5t^2)=0
We get rid of parentheses
5t^2-10t+495=0
a = 5; b = -10; c = +495;
Δ = b2-4ac
Δ = -102-4·5·495
Δ = -9800
Delta is less than zero, so there is no solution for the equation
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